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Hasil kali dari [tex]\sf (ab + \frac{1}{b})[/tex] dengan [tex]\sf (\frac{1}{ab} - b)[/tex]
Hasil kali dari [tex]\sf (ab + \frac{1}{b})[/tex] dengan [tex]\sf (\frac{1}{ab} - b)[/tex]
Penyelesaian:
[tex]\sf (ab + \frac{1}{b})\sf (\frac{1}{ab} - b) [/tex]
=1-ab²+1/a -1
=-ab²+1/a
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
[tex] \sf(ab + \frac{1}{b})(\frac{1}{ab} - b)[/tex]
[tex] \sf = (ab)( \frac{1}{ab} ) - (ab)(b) + ( \frac{1}{b} )( \frac{1}{ab} ) - ( \frac{1}{b} )(b)[/tex]
[tex] \sf = \frac{ab}{ab} -a {b}^{2} + \frac{1}{a {b}^{2} } - \frac{b}{b} [/tex]
[tex] \sf = 1 -a {b}^{2} + \frac{1}{a {b}^{2} } - 1[/tex]
[tex] \sf = - a {b}^{2} + \frac{1}{a {b}^{2} } [/tex]
[tex]\sf = - \frac{ {a}^{2} {b}^{4} }{a {b}^{2} } + \frac{1}{a {b}^{2} }[/tex]
[tex] \boxed{\sf = \frac{1 - {a}^{2} {b}^{4} }{a {b}^{2} } }[/tex]
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